Chapter 9: Straight Lines

Math • Class 11

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Chapter Analysis

Intermediate24 pages • English

Quick Summary

This chapter on 'Straight Lines' covers the fundamental concepts of slopes, equations, and properties of straight lines in a plane. It delves into the different forms of line equations, conditions for parallelism and perpendicularity, and derives equations based on various parameters like slope-intercept and two-point forms. Additionally, it discusses the geometric interpretations like the distance of a point from a line and the area of triangles formed by lines.

Key Topics

  • Slope of a line
  • Equation of a line
  • Parallel and perpendicular lines
  • Distance from a point to a line
  • Different forms of line equations
  • Intercepts of a line
  • Collinearity of points
  • Area calculation of geometrical figures

Learning Objectives

  • Understand how to calculate the slope of a line between two points.
  • Learn to write the equation of a line in different forms.
  • Identify the conditions for parallel and perpendicular lines.
  • Calculate the distance of a point from a line.
  • Utilize the slope-intercept and point-slope forms to derive line equations.

Questions in Chapter

Exercise 9.1: Draw a quadrilateral in the Cartesian plane, whose vertices are (–4, 5), (0, 7), (5, –5) and (–4, –2). Also, find its area.

Page 158

Exercise 9.3: Find the distance of the point (–1, 1) from the line 12(x + 6) = 5(y – 2).

Page 167

Miscellaneous Exercise: Find the values of k for which the line (k–3) x – (4 – k²) y + k² –7k + 6 = 0 is (a) Parallel to the x-axis, (b) Parallel to the y-axis, (c) Passing through the origin.

Page 173

Additional Practice Questions

What is the equation of a line parallel to the y-axis and passing through the point (3, -7)?

easy

Answer: The equation is x = 3, since a line parallel to the y-axis has the form x = constant.

Find the slope of a line passing through the points (2, 3) and (4, 11).

medium

Answer: The slope m is calculated as (11 - 3) / (4 - 2) = 8 / 2 = 4.

Describe the conditions under which two lines are perpendicular in a plane.

easy

Answer: Two lines are perpendicular if the product of their slopes is -1.

A line makes an angle of 45° with the positive direction of the x-axis. What is its slope?

easy

Answer: The slope m of the line is tan(45°) = 1.

How do you find the equation of a line given a point (1, 2) and its slope 3?

medium

Answer: Using the point-slope form, y - 2 = 3(x - 1), the equation simplifies to y = 3x - 1.